Question

一道初一计算（2+1）(2^2+1)(2^4+1)(2^8+1）-2^16

Answer 1

（2+1）(2^2+1)(2^4+1)(2^8+1）-2^16

=(2-1)（2+1）(2^2+1)(2^4+1)(2^8+1）-2^16

=(2^2-1)(2^2+1)(2^4+1)(2^8+1）-2^16

=(2^4-1)(2^4+1)(2^8+1）-2^16

=2^16-2^16

=0