(2a+c)cosB+bcosC=0
2a cosB+c cosB+b cosC=0
2sinA cosB+sinC cosB+sinB cosC=0
2sinA cosB+sin(B+C)=0 ,
( sin(B+C)=sin(π-B-C)=sinA)
2sinA cosB+sinA=0 (两边同除掉sinA)
2 cosB+1=0
cosB=-1/2
(2a+c)cosB+bcosC=0
2a cosB+c cosB+b cosC=0
2sinA cosB+sinC cosB+sinB cosC=0
2sinA cosB+sin(B+C)=0 ,
( sin(B+C)=sin(π-B-C)=sinA)
2sinA cosB+sinA=0 (两边同除掉sinA)
2 cosB+1=0
cosB=-1/2