Question

(根号3—i)的12次,不要死算

Answer 1

原式=[2(√3/2-i/2)]^12

=[2(cos11π/6+isin11π/6)]^12

=2^12[cos(12×11π/6)+isin(12×11π/6)]

=2^12(cos22π+isin22π)

=2^12*1

=4096