Question

若8（a+2）平方+3│b-3│+16(c+0.5）的平方=0,求（a的b次方+2c）的平方

Answer 1

8（a+2）平方+3│b-3│+16(c+0.5）的平方=0 ==> a+2 = 0, b -3 = 0, c +0.5 = 0 ==> a = -2, b = 3, c = -0.5 (a^b + 2c)^2 = [(-2)^3 + 2 * (-0.5)]^2 = [-8 - 1]^2 = 9^2 = 81

记得采纳啊