Question

(100-100x)^2+(80-80x)^2=(10√41)^2简便计算

Answer 1

100^2(1-x)^2+80^2(1-x)^2=100×41

(10000+6400)(1-x)^2=4100

(1-x)^2=1/4

1-x=±1/2

x=1/2,x=3/2