齐次方程.y^2+x^2dy/dx=xydy
3个回答
u+xu'=u^2/(u-1)
移向先
xu'=u^2/(u-1)-u
通分
xu'=u^2/(u-1)-u(u-1)/(u-1)
=(u^2-u^2+u)/(u-1)
=u/(u-1)
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