Question

已知如图点E F在BC上 AF=AE 角1=角2 AB=AC 求证三角形AFB≌AEC

Answer 1

证明：

∵ ∠BAF=∠EAF+∠1 ,∠CAE=∠EAF+∠2,且∠1 =∠2

∴ ∠BAF=∠CAE

又 ∵ AB=AC ,∠B =∠C

∴ AFB≌AEC