x[x-1]-[x^2-y]=2
x^2-x-x^2+y=2
y-x=2
x-y=-2
(3x^2+3y^2)/2-3xy
=(3x^2+3y^2-6xy)/2
=3(x-y)^2/2
=3*(-2)^2/2
=6
x[x-1]-[x^2-y]=2,3x^2加3y^2/2-3xy等于多少
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