弧长C=23.5米 拱高H=0.7米求半径R?
Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*SIN(C/(2*Rn))-H))*Rn
R0=98
R1=98.4942
R2=98.4992
R3=98.4992
R=98.4992米
弧长C=23.5米 拱高H=0.7米求半径R?
Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*SIN(C/(2*Rn))-H))*Rn
R0=98
R1=98.4942
R2=98.4992
R3=98.4992
R=98.4992米