原式=25+(-5)^0+4^[2log4 2]=25+1+2²=30
求值:3^(log3 (25) )+(-C(5,4)^(log2 1)+16^(log4(2sin(π/2))=
1个回答
相关问题
-
2^2*16^(3/4)+2log根号2+1/2log25+(logπ)^0
-
求值(log2 5+log4 1/5)(log5 2+log25 1/2)
-
(log25 2+log5 1/8)(log2 5+log4 根5)求值
-
log10是什么?log 75 - log 3 + log 4=log25+log3-log3+2log2=2log5+
-
高中数学对数计算求值(log2 125+log4 25+log8 5)*(log125 8+log25 4+log5 2
-
求:(log2 125+log4 25+log8 5)(log125 8+log25 4+log5 2);
-
log4^25-2log4^10+log2^9×log3^根号5×log5^2
-
求值(log3(2)+log9(2))*(log4(3)+log8(3))
-
lg^2*5+lg21g50 log3*根号3/3+log8*4 4^log2*5+2*5^log25*4
-
求值:log2(32)+log2(6)-log2(3/4)