y=asinx+btanx+3满足f(π／5)=5

2个回答

∵f（π/5）=asinπ/5+btanπ/5+3=5,∴asinπ/5+btanπ/5=2,
∴f（99π/5）=asin99π/5+btan99π/5+3=asin(20π-π/5)+btan(20π/5)+3=-asinπ/5-btanπ/5+3
=-（asinπ/5+btanπ/5）+3=-2+3=1

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