1000g 5%浓度的NaOH溶液,体积约为1L
其中,氢氧化钠物质的量的浓度为:
1000*5%/40=1.25MOL/L
[OH-]:1.25MOL/L
PH
=-lg[H+]
=-lg1*10^-14/[OH-]
=14+lg[OH-]
=14+lg1.25
=14+0.1
=14.1
1000g 5%浓度的NaOH溶液,体积约为1L
其中,氢氧化钠物质的量的浓度为:
1000*5%/40=1.25MOL/L
[OH-]:1.25MOL/L
PH
=-lg[H+]
=-lg1*10^-14/[OH-]
=14+lg[OH-]
=14+lg1.25
=14+0.1
=14.1