Question

把3x^2+1/x^4-1化成分子中不含x的若干个分式的和

Answer 1

LZ的题目是不是括号没括出来?

(3x^2+1)/(x^4-1)

如果是这样,解题如下：

原式=(3x^2+1)/(x^2+1)(x^2-1)

=[3(x^2+1)-2]/(x^2+1)(x^2-1)

=3/(x^2-1)-2/(x^2+1)(x^2-1)

=(3/2)[1/{x-1)-1/(x+1)]-(1/2)[1/(x-1)-1/(x+1)]+1/(x^2+1)

=1/(x-1)-1/(x+1)+1/(x^2+1)

这个是不是你要的结果?