条件有误:AD⊥OC应为AD⊥EC
OE=OF
证明:
∵OC⊥AB
∴∠AOC=∠BOC=90
∴∠OCE+∠AEC=90
∵AD⊥CE
∴∠BAD+∠AEC=90
∴∠OCE=∠BAD
∵OA=OC
∴△AOF≌△COE (ASA)
∴OE=OF
条件有误:AD⊥OC应为AD⊥EC
OE=OF
证明:
∵OC⊥AB
∴∠AOC=∠BOC=90
∴∠OCE+∠AEC=90
∵AD⊥CE
∴∠BAD+∠AEC=90
∴∠OCE=∠BAD
∵OA=OC
∴△AOF≌△COE (ASA)
∴OE=OF