令a=x-y
b=x/y
则x=by
a=by-y
y=a/(b-1)
x=ab/(b-1)
则x+y=a(b+1)/(b-1)
所以x²-y²=a²(b+1)/(b-1)
f(a,b)=a²(b+1)/(b-1)
f(x,y)=x²(y+1)/(y-1)
令a=x-y
b=x/y
则x=by
a=by-y
y=a/(b-1)
x=ab/(b-1)
则x+y=a(b+1)/(b-1)
所以x²-y²=a²(b+1)/(b-1)
f(a,b)=a²(b+1)/(b-1)
f(x,y)=x²(y+1)/(y-1)