答:
(1)
√3sin2A=1-cos2A=2sin²A
2√3sinAcosA=2sin²A>0
所以:tanA=√3
所以:A=60°
(2)B=π/4=45°
根据正弦定理得:
a/sinA=b/sinB=c/sinC=2R
b=asinB/sinA
=1*sin45°/sin60°
=√6/3
所以:b=√6/3
答:
(1)
√3sin2A=1-cos2A=2sin²A
2√3sinAcosA=2sin²A>0
所以:tanA=√3
所以:A=60°
(2)B=π/4=45°
根据正弦定理得:
a/sinA=b/sinB=c/sinC=2R
b=asinB/sinA
=1*sin45°/sin60°
=√6/3
所以:b=√6/3