计算16^(1/log6(4))+49^(1/log8(7))
1个回答
=16^(log4(6))+49^(log7(8))
=[4^(log4(6))]^2+[7^(log7(8))]^2
=6^2+8^2
=100
相关问题
a=25^1/(log6 5)b=49^log8(7) 计算lg(a+b)
log7(1/8) * (log8 (25)+log2 (5))* log5 (49) 怎么求
计算下列数值.(1):log2 4=( )log2 16=( )log2 64=( )(2)观察(1)中三数4,16,6
log₃8 x log₂49 x log7 27=?
log2(3)*log3(4)*log4(5)*log5(6)*log6(7)*log7(8)=?
log2 49*log3 16*log7 27=?(空格后是真数)
计算:(log4 9+log8 3)(log3 2+log9 2)-log1/3 4√81
log计算题7^1-log7^5
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)
对数计算1.{log(4)(3)+ log(8) (3)} X {log(3)(2)+log(9)(2)}2.{log(