f'(x)=(x^2+2x-a)/(x+1)^2
1、则f'(1)=1/2 即(3-a)4=1/2故a=1
2、则f'(1)=0 即(3-a)4=1/2故a=3
则f'(x)=(x^2+2x-3)/(x+1)^2
令f'(x)=0则x=1或-3
则当x>1或x
f'(x)=(x^2+2x-a)/(x+1)^2
1、则f'(1)=1/2 即(3-a)4=1/2故a=1
2、则f'(1)=0 即(3-a)4=1/2故a=3
则f'(x)=(x^2+2x-3)/(x+1)^2
令f'(x)=0则x=1或-3
则当x>1或x