[(xy-1-x+y)÷(y-1)+(y-1)]×2求化简
2个回答
原式={[(x(y-1)+(y-1)]÷(y-1)+(y+1)}×2
=[x+1+y+1)×2
=2x+2y+4
相关问题
化简求值:(X×根号X+X×根号y)÷(XY-Y²)-(X+根号XY+Y)÷X×根号X-Y×根号Y,其中X=1
先化简,再求值,【1/(x-y)-1/(x+y)】÷【2y/(x-2xy+y)】,其中x=1+√2,y=1-√2
化简求值[1-(2x/x+y)]÷ (x²-2xy+y²/3x+3y)+(x²+xy/x&
化简求值,4x^5y³÷[x^4y³÷[x³y÷(x³y²÷2xy²]},其中x=-1/2,y=3
先化简再求值-1/2x²×(2xy²-4x²y²)-4x²y×(-xy
化简求值: [(xy+2)(xy-2)-2x²y²+4]÷(xy), 其中x=20,y=- 1/25
化简(x²-y²/xy)²÷(x+y)²×(x/x-y)³求当x=3
先化简再求值:xy^3÷(-xy)+(x+2y)(x-2y),其中x=根号2,y=1
先化简,再求值:(1/x-y - 1/x+y)÷2y/x的平方-2xy+y的平方,其中x=1
1÷xy÷(1÷y-1÷x)化简是什么