i(i+1)的平方/i-1的值求数学大神,快快快! - 知识问答

i(i+1)的平方/i-1的值求数学大神,快快快!

1个回答

i(i+1)²/(i-1)
=i(-1+2i+1)/(i-1)
=i(2i)/(i-1)
=-2/(i-1)
=-2(i+1)/[(i-1)(i+1)]
=2(i+1)/(i²-1)
=-2(i+1)/(-2)
=i+1
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