Question

y=4x^2+x-8的对称轴和顶点坐标

Answer 1

∵a=4,b=1,c=-8

∴-b/(2a)=-1/(2×4)=-1/8

(4ac-b²)/(4a)=[4×4×(-8)]-1²]/(4×4)

=-129/16

∴抛物线y=4x²+x-8的对称轴是直线X=-1/8,顶点坐标是(-1/8,-129/16)