y''=sinx的通解

y'=C1-cosx (C1是积分常数)==>y=C1x-sinx+C2 (C2是积分常数)∴原方程的通解是y=C1x-si"}}}'>

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∵y''=sinx ==>y'=C1-cosx (C1是积分常数)
==>y=C1x-sinx+C2 (C2是积分常数)
∴原方程的通解是y=C1x-sinx+C2.