z=f(x+y,x-y),则dz=?
1个回答
dz=f1d(x+y)+f2d(x-y)=f1(dx+dy)+f2(dx-dy)=(f1+f2)dx+(f1-f2)dy.f1,f2代表二元函数f对其两个自变量的偏导数.
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