Question

1.y=(1-x)/(1+x) 2.(ax+b)/(cx+d) ab-bc≠0 3.y=2^x/(2^x+1)

Answer 1

(1+x) y = 1-x => (y+1)x = 1-y => x = (1-y)/(1+y)

y(cx+d) = ax + b => (cy -a)x= b-dy => x = (b-dy)/(cy-a)

(2^x+1)y = 2^x => 2^x(1-y) = y => 2^x = y/(1-y) => x = ln[y/(1-y)]/ln2