∵AB=AC,AD⊥BC
∴BD=CD
∴C△ABD=C△ACD
∴C△ABD+C△ACD=2C△ABD=32㎝
又∵C△ABD+C△ACD=AB+BD+AD+AC+CD+AD=AB+AC+BC+2AD=C△ABC+2AD
∴AD=0.5(C△ABD+C△ACD-C△ABC)=6㎝
∵AB=AC,AD⊥BC
∴BD=CD
∴C△ABD=C△ACD
∴C△ABD+C△ACD=2C△ABD=32㎝
又∵C△ABD+C△ACD=AB+BD+AD+AC+CD+AD=AB+AC+BC+2AD=C△ABC+2AD
∴AD=0.5(C△ABD+C△ACD-C△ABC)=6㎝