Question

已知x²-2xy+y²-x+y-1=0,求x-y的值

Answer 1

已知x²-2xy+y²-x+y-1=0,求x-y的值

（x-y）²-(x-y)-1=0;

[(x-y)²-(x-y)+1/4]=1+1/4;

(x-y-1/2)²=5/4;

x-y-1/2=±√5/2;

x-y=1/2±√5/2;

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