两道化简求值,要有非常详细的过程

1个回答

  • 1.y/{[(x+2y)(x-2y)-(x+2y)^2]/2}

    =2y/[(x+2y)(x-2y)-(x+2y)^2]

    =2y/[x^2-4y^2-(x^2+4xy+4y^2)]

    =2y/[x^2-4y^2-x^2-4xy-4y^2]

    =2y/[-4xy-8y^2]

    =2y/-4y[x+2y]

    =-1/2[x+2y]

    将x=1,y=1/4代入,得

    -1/2[x+2y]

    =-1/2[1+2x1/4]

    =-1/2[3/2]

    =-1/3

    2.(2a+b)^2-(2a-b)(a+b)-2(a-2b)(a+2b)

    =4a^2+4ab+b^2-(2a^2+2ab-ab-b^2)-2(a^2-4b^2)

    =4a^2+4ab+b^2-2a^2-2ab+ab+b^2-2a^2+8b^2

    =3ab+10b^2

    将a=2分之1,b=-2代入,得

    3ab+10b^2

    =3x1/2x(-2)+10x(-2)^2

    =-3+40

    =37