Question

(1+2分之1)(1+2的平方分之1)(1+2的立方分之1)（1+2的4方分之1）.（1+2的16次方分之1）

Answer 1

应该是这样吧：

(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)(1+1/2^16)

=2(1-1/2) (1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)(1+1/2^16)

=(1-1/2^2)(1+1/2^2)(1+1/2^3)(1+1/2^4)(1+1/2^8)(1+1/2^16)

=2(1-1/2^4)(1+1/2^4)(1+1/2^8)(1+1/2^16)

=2(1-1/2^8)(1+1/2^8)(1+1/2^16)

=2(1-1/2^16)(1+1/2^16)

=2(1+1/2^32)

=2-1/2^31