Question

已知f（x）=?（a的x次方-a的－x次方）,g（x）=?（a的x次方+a的－x次方)

Answer 1

[f(x)]2+g[(x)]2=[(a)x-(a)(-x)]2+[(a)x+(a)(-x)]2=[(a)x]2-2*(a)x*(a)(-x)+[(a)(-x)]2+[(a)x]2+2*(a)x*(a)(-x)+[(a)(-x)]2=2(a)(2x)+2(a)(-2x)=2[(a)(2x)+(a)(-2x)]=2g(2x)