Question

x加2分之3x减x-2分之x的差除以x方-4分之2x怎么算啊.

Answer 1

[3x/(x+2)-x/(x-2)]/[2x/(x^2-4)]

={3x(x-2)/[(x+2)(x-2)]-x(x+2)/[(x+2)(x-2)}/[2x/(x^2-4)]

={[2x(x-2)]/[(x+2)(x-2)]}/{2x/[(x+2)(x-2)}

=x-2