6xy+9x^2-m^2+y^2=（3x+y)²-m²=(3x+y+m)(3x+y-m)
x^2·y-4y(x+y)^2=y*[x²-4(x+y)²]=y(x-2x-2y)(x+2x+2y)=-y(x+2y)(3x+2y)
a^2+4b+b^2-2a+5=0,求a,b
a²-2a+1+b²+4b+4=0
(a-1)+(b+2)²=0
a-1=0 b+2=0
∴a=1
b=-2
因式分解：6xy+9x^2-m^2+y^2=?x^2·y-4y(x+y)^2+?
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