P=根号下[(n²-1)/(n-1)]与Q=根号下{[(n+1)²-1]/[(n+1)-1]}?
P=根号下[(n²-1)/(n-1)]=根号下[(n+1)(n-1)/(n-1)]=根号下(n+1),(n为大于1的整数)
Q=根号下{[(n+1)²-1]/[(n+1)-1]}=根号下{[(n+1)+1][(n+1)-1]/[(n+1)-1]}=根号下(n+2),(n为大于1的整数)
P
P=根号下[(n²-1)/(n-1)]与Q=根号下{[(n+1)²-1]/[(n+1)-1]}?
P=根号下[(n²-1)/(n-1)]=根号下[(n+1)(n-1)/(n-1)]=根号下(n+1),(n为大于1的整数)
Q=根号下{[(n+1)²-1]/[(n+1)-1]}=根号下{[(n+1)+1][(n+1)-1]/[(n+1)-1]}=根号下(n+2),(n为大于1的整数)
P