Question

如图,三角形ABC中,AD⊥BC,AE平分∠BAC,1,若∠B=70°,∠C=34°,求∠DAE的度数2,若∠DAE=1

Answer 1

⑴∵AE平分∠BAC∴∠CAE＝∠BAE＝180°－∠B－∠C＝76°

∵AD⊥BC∴∠CAD＝90°－∠C＝56°

∴∠DAE＝∠CAE－∠CAD＝20°

⑵Sorry,I don't know