原式=[(2a-b)/(a+b)-b/(a-b)]/[(a-2b)/(a+b)]对吗?
=(2a^2-3ab+b^2-ab-b^2)/[(a+b)(a-b)]*(a+b)/(a-2b)
=2a(a-2b)/[(a-b)(a-2b)]
=2a/(a-b)
原式=[(2a-b)/(a+b)-b/(a-b)]/[(a-2b)/(a+b)]对吗?
=(2a^2-3ab+b^2-ab-b^2)/[(a+b)(a-b)]*(a+b)/(a-2b)
=2a(a-2b)/[(a-b)(a-2b)]
=2a/(a-b)