多项式2x²+y²+4x+10y+9的最小值是

1个回答

  • 2x²+y²+4x+10y+9

    =2(x²+2x+1)+(y²+10y+25)-18

    =2(x+1)²+(y+5)²-18

    最小值是-18

    被除式=除式×商+余式

    所以被除式=(3x+1)×(x-1)-5

    =3x²-2x-6

    m^5+m^3-20m

    =m(m^4+m^2-20)

    =m(m^2-4)(m^2+5)

    =m(m+2)(m-2)(m^2+5)

    x^4n-4x^2n-45

    =(x^2n-9)(x^2n+4)

    =(x^n+3)(x^n-3)(x^2n+4)

    (m^2-2m)^2-2m^2+4m-3

    =(m^2-2m)^2-2(m^2-2m)-3

    =(m^2-2m-3)(m^2-2m+1)

    =(m-3)(m+1)(m-1)^2

    a^4-13a^2b^2+36b^4

    =(a^2-4b^2)(a^2-9b^2)

    =(a+2b)(a-2b)(a+3b)(a-3b)

    (x^2+4x)^2-x^2-4x-20

    =(x^2+4x)^2-(x^2+4x)-20

    =(x^2+4x-5)(x^2+4x+4)

    =(x-1)(x+5)(x+2)^2

    a^4b^4-6a^2b^2-27

    =(a^2b^2-9)(a^2b^2+3)

    =(ab+3)(ab-3)(a^2b^2+3)