Question

（x+y)+(2x+1/1*2y)+(3x+1/2*3y)+.+(9x+1/8*9y) 当X=2,Y=9时,求代数式的值

Answer 1

（x+y)+(2x+1/1*2y)+(3x+1/2*3y)+.+(9x+1/8*9y)

= x(1+2+3+...9) + y { 1+1/(1*2)+1/(2*3)+1/(3*4)+...1/(8*9) }

= x(1+9)*9/2 + y { 1+1-1/2+1/2-1/3+1/3-1/4+...1/8-1/9) }

= 45x + y(2-1/9)

= 45x+2y-y/9

= 45*2 + 2*9 - 9/9

= 90+18-1

= 107