周期是2(7π/12-π/12)=π,则w=2,及A=2,此时f(x)=2sin(2x+φ).又x=π/12时取得最小值-2,代入,计算出φ=-2π/3.则f(x)=2sin(2x-2π/3)
已知函数f(x)=Asin(ωx+φ)(A>0,|φ|
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