Question

{[1/(1-x)]+[(1-3x)/(1-x2)]}的极限,x趋于1

Answer 1

[1/(1-x)]+[(1-3x)/(1-x^2)] (这里x^2=x的平方）

=[(1+x)/(1-x^2)]+[(1-3x)/(1-x^2)]

=[(1+x)+(1-3x)]/(1-x^2)

=[2(1-x)]/(1-x^2)

=2/(1+x)

因此,当x趋于1时,所求极限为1.