[(x-y/2)^2-(x+y/2)^2]÷(-1

[(x-y/2)^2-(x+y/2)^2]÷(-1/2xy).

1个回答

[(x+y)^2-(x-y)^2]÷(1/2xy)
求助：x²+y²/ x²+2xy+y²+2/xy÷（1/x+1/y）²
[(x-y/2)^2-(x+y/2)^2]÷(-1/2xy).
(-6x^2y^3+2x^2y-1/2xy)÷(-1/2xy)
(1/x-y+1/x+y)÷xy/x^2-y^2
求值（x^2+xy)/(x^2-2xy-3y^2)*(3y-x)/(x-y)+(x^-1+y^-1)÷(x^-1-y^-
求值（x^2+xy)/(x^2-2xy-3y^2)*(3y-x)/(x-y)+(x^-1+y^-1)÷(x^-1-y^-
x*（9x^3y-3xy^2）÷（-3x^2y）= 【（x+y）^2-（x-y）^2】÷（-4xy）=
(x+y)(x-y)+(x-y)^2-(6x^2×y÷2y-2xy^2÷2y)其中x=-3,y=1/3
1.【x(x^2y^2-xy)-y(x^2-x^3y)]÷3x^2y