Question

求x的值：（1）log2底(x²－2﹚＝0;﹙2﹚log﹙2x²﹚底﹙3x²＋2x－1﹚＝

Answer 1

（1）x^2-2=1 => x^2=3 =>x=根号3或-根号3

（2）3x²＋2x－1=2x^2 =>x^2+2x-1=0 =>(x+1)^2=2 =>x=-1+根号2或-1-根号2