Question

ab-ab+bc-bc+ca-ca.分解因式

Answer 1

=ab-ac+ac-ab+bc-bc =a(b-c)-a(b+c)(b-c)+bc(b-c) =(b-c)(a-ab-ac+bc) =(b-c)[a(a-b)-c(a-b)] =(a-b)(b-c)(a-c)