Question

函数y=sin2x+cos2x,当x=_____时,ymax=_____,周期为_____；函数y=sinx+√2cos

Answer 1

(1).y=sin2x+cos2x=√2sin(2x+π/4)

当x=kπ+π/8时,ymax=√2,周期T=2π/2=π

(2).y=sinx+√2cosx=√3sin(x+φ)

最大值为√3,周期T=2π/1=2π

(3).y=sinxcosx=1/2sin2x

当x=kπ+π/4时,yamx=1/2