Question

已知(2x-1)^6=ax6+bx^5+cx^4+dx^3+ex^2+fx+g

Answer 1

令x=1

a+b+c+d+e+f+g=(2*1-1)^6=1

令x=-1

a-b+c-d+e-f+g=[2*(-1)-1]^6=3^6

所以a+c+e+g=[(a+b+c+d+e+f+g)+(a-b+c-d+e-f+g)]/2

=(3^6+1)/2

=365