初一数学,计算题跟化简题要详细过程,谢谢,急要

1个回答

  • 1、(1)2/-m+3/m=(1/m) (2)(4/m+3)+(m-1/m+3)=1

    2、化简(x²/y-x)-(y²/y-x)的结果是(A)

    A、-x-y B、y-x C、x-y D、x+y

    3、计算

    (1)(x/x-2)-(2/x-2)

    =(x-2)/(x-2)

    =1

    (2)(x+5y/x+y)+(x-3y/x+y)

    =(x+5y+x-3y)/(x+y)

    =(2x+2y)/(x+y)

    =2

    (3)[x²-y/(x-3)²]-[9-y/(3-x)²]

    =(x²-y-9+y)/(x-3)²

    =(x²-9)/(x-3)²

    =(x+3)(x-3)/(x-3)²

    =(x+3)/(x-3)

    (4)(a²-1/a²-2a)+(4a-5/2a-a²)

    =(a²-1-4a+5)/(a²-2a)

    =(a-2)²/a(a-2)

    =(a-2)/a

    (5)(9m²/-3m-n)+(n²/n+3m)

    =(n²-9m²)/(n+3m)

    =(n+3m)(n-3m)/(n+3m)

    =n-3m

    4、化简:[a²-b²/(a-b)(a-c)]+[c²-b²/(a-b)(c-a)]

    =(a²-b²-c²+b²)/(a-b)(a-c)

    =(a+c)(a-c)/(a-b)(a-c)

    =(a+c)/(a-b)

    5、化简:(x²+x/x²-1)-(x+1/x-1)

    =x(x+1)/x(x-1) - (x+1/x-1)

    = (x+1/x-1)- (x+1/x-1)

    =0