√3 *x（4次）-√2 *x（x方-√2+1）+3*x（3次）+（√3-√6）x方+x-√6
=√3 *x^4-√2*x（x^2-√2+1）+3*x^3+（√3-√6）x^2+x-√6
=√3 *x^4-√2*x^3+√2(√2-1）x+3*x^3+（√3-√6）x^2+x-√6
=√3 *x^4+(3-√2)*x^3+（√3-√6）x^2+√2(√2-1）x+x-√6
=√3 *x^4+(3-√2)*x^3+（√3-√6）x^2+(3-√2)x-√6
=√3 *x^4+（√3-√6）x^2-√6 +(3-√2)*x^3+(3-√2)x
=[√3 *x^2-√6][x^2+1]+(3-√2)*x[x^2+1]
=√3[x^2-√2][x^2+1]+(3-√2)*x[x^2+1]
=(x^2+1)[√3(x^2-√2)+(3-√2)*x]
=(x^2+1)(√3x^2-√6+3x-√2x)
=(x^2+1)(√3x^2-√6+3x-√2x)
=(x^2+1)(√3x-√2)(x+√3)