已知x²y²-8xy+4x²+y²+4=0,求y-2x+(yx/2)^2012的
2个回答
x²y²-8xy+4x²+y²+4=0,
(2x-y)²+x²y²-4xy+4=0
(2x-y)²+(xy-2)²=0
2x=y或xy=2
y-2x+(yx/2)^2012
=0+1=1
相关问题
已知x+y=6,xy=-4,求:(5x-4y-3yx)-(8x-y+2xy)的值
已知实数x、y满足|2x-y+1|+2(3x-2y+4)2=0,求代数式1−x−yx−2y÷x2−y2x2−4xy+4y
已知x-3y=0,求[2x+yx2-2xy+y2
已知x=2007,y=2008,则x2+2xy+y25x2−4xy÷x+y5x−4y+x2−yx=______.
(2012•朝阳区二模)已知y-2x=0,求x2yx2+2xy+y2•(1x+1y)的值.
已知x^2+4y^2-4x+4y+5=0,求(x^4-y^4/2x^2+xy-y^2)*(2x-y/xy-y^2)/(x
已知|x²-2xy-8y²|+2√x²-4xy+4y²-1=0,求3x+6y的值
已知2x+y=0,求x-2y/x²+xy乘(x²-y²)÷x²-4xy+4y
已知(y+2x)/xy=3/2,求(4x+3xy+2y)/(-4x+8xy-2y)
已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值?