因为A垂直于C,所以AC=0.即A(xA+yB)=AxA+AyB=0
左乘A,A^2xA+A^2yB=0即25xA+25yB=0
所以xA+yB=0……(1)
(1)式右乘A,可得xA^2+yBA=0即25x+24y=0……(2)
(1)式又乘B,可得xAB+yB^2=0即24x+25y=0……(3)
(2)-(3)可得x=y,所以x=y=0
因为A垂直于C,所以AC=0.即A(xA+yB)=AxA+AyB=0
左乘A,A^2xA+A^2yB=0即25xA+25yB=0
所以xA+yB=0……(1)
(1)式右乘A,可得xA^2+yBA=0即25x+24y=0……(2)
(1)式又乘B,可得xAB+yB^2=0即24x+25y=0……(3)
(2)-(3)可得x=y,所以x=y=0