Question

1.在标准状况下,2.2g CO2的体积是多少?

Answer 1

1.

V=22.4*n=22.4*(m/M)=22.4*(2.2/44)=1.12L

2.

M=m/n=m/(V/22.4)=1.92/(672/1000*22.4)=64

3.

Zn + 2HCl = ZnCl + H2

1 x=1

V=22.4*nH2=22.4*nZn=22.4*m/M=22.4*26/65=8.96L

4.

nKCl:nNaCl=nK:nNa=3:1

mKCl:nNaCl=MKCl*nKCl:MNaCl*nNaCl=74.5*3:58.5=223.5:58.5

wKCl=mKCl/m总=223.5/(223.5+58.5)=79.25%

m=0.75*MKCl+0.25*MNaCl=0.75*74.5+0.25*58.5=70.5g