(1)
an=1/2(a(n-1)+a(n-2))
an - a(n-1) =-(1/2)[ a(n-1) -a(n-2) ]
= (-1/2)^(n-2) .(a2-a1)
= (-1/2)^(n-2)
an - a2 = (-1/2) +(-1/2)^2 +...+(-1/2)^(...
数列an满足a1=1,a2=2,a(n)=1/2(a(n-1)+a(n-2)),(n=3,4.....),数列﹛bn﹜是
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