Question

平方差公式,本人一定采纳,

Answer 1

原式=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)/(2^2-1)

=(2^4-1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)/(2^2-1)

=(2^8-1)(2^8+1)(2^16+1)(2^32+1)/(2^2-1)

=(2^16-1)(2^16+1)(2^32+1)/(2^2-1)

==(2^32-1)(2^32+1)/(2^2-1)

=(2^64-1)/3